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    COPOLYMER WITH POLYAMIDE BLOCKS AND A POLYETHER BLOCK
    1.
    发明申请
    COPOLYMER WITH POLYAMIDE BLOCKS AND A POLYETHER BLOCK 有权
    共聚物与聚酰胺块和聚醚嵌段

    公开(公告)号：US20160251484A1

    公开(公告)日：2016-09-01

    申请号：US15027603

    申请日：2014-10-06

    Applicant: ARKEMA FRANCE

    Inventor： Frederic MALET

    IPC: C08G81/00

    CPC classification number: C08G81/00 ,  C08G69/40

    Abstract: The invention relates to a copolymer comprising at least two distinct polyamide blocks and at least one polyether block, and a method for preparation of said copolymer comprising the following steps:—in a first step, the polyamide block PA1 is prepared by polycondensation of chosen monomers: amino acids, lactames or diamines and dicarboxylic acids, in the presence of an appropriate chain limiter;—then, in a second optional step, the polyamide PA1 block obtained is reacted with all or part of the polyether PE blocks, in the presence or absence of a catalyst;—in a third step, the polyamide PA2 block is prepared by polycondensation of the chosen isomers: amino acids, lactams or diamines and dicarboxylic acids, in the presence of an appropriate chain limiter;—in a fourth optional step, the polyamide PA2 block obtained is reacted with all or part of the polyether PE blocks, in the presence or absence of a catalyst;—in a fifth step, PA1 or the reaction medium from step 2 is reacted with PA2 or the reaction medium from step 4 and with PE or the remainder of PE not added in step 2 or 4.

    Abstract translation: 本发明涉及包含至少两个不同的聚酰胺嵌段和至少一个聚醚嵌段的共聚物，以及制备所述共聚物的方法，包括以下步骤：在第一步骤中，聚酰胺嵌段PA1通过选择的单体 ：在适当的限制剂存在下，氨基酸，内酰胺或二胺和二羧酸;以及在第二任选步骤中，所获得的聚酰胺PA1嵌段与全部或部分聚醚PE嵌段反应， 不存在催化剂; - 在第三步中，聚酰胺PA2嵌段通过所选异构体的缩聚制备：氨基酸，内酰胺或二胺和二羧酸，在适当的限制剂存在下; - 在第四任选步骤中， 获得的聚酰胺PA2嵌段在存在或不存在催化剂的情况下与全部或部分聚醚PE嵌段反应;在第五步中，将PA1或来自步骤2的反应介质反应 与PA2或来自步骤4的反应介质和PE或PE的其余部分未在步骤2或4中加入。

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