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发明公开
CN103554466A 含磷、氯、锑阻燃聚醚多元醇的制备方法 有权 质押

含磷、氯、锑阻燃聚醚多元醇的制备方法
摘要：
本发明具体涉及一种含磷、氯、锑阻燃聚醚多元醇的制备方法，由如下重量份数的原料制成：三氯氧磷121～180份、甘油160～210份、蔗糖10～60份、三氯化锑20～80份、环氧丙烷600～850份、环氧氯丙烷600～900份；本发明的聚醚多元醇与现有常规聚醚多元醇具有更好的阻燃效果；制备方法操作简单，产率高。
摘要（英）：

The invention specifically relates to a preparation method of a flame-retardant polyether polyol containing phosphorus, chlorine and antimony. The flame-retardant polyether polyol containing phosphorus, chlorine and antimony is prepared from the following raw materials in parts by weight: 121-180 parts of phosphorus oxychloride, 160-210 parts of glycerinum, 10-60 parts of saccharose, 20-80 parts of antimony trichloride, 600-850 parts of epoxypropane and 600-900 parts of epoxy chloropropane. Compared with conventional polyether polyol, the polyether polyol provided by the invention has a better flame retardant effect, and the preparation method is simple to operate and high in yield.

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